0.999... (where the 9's go on to infinity) is equal to 1.

here's how:

One divided by three equals 0.333(to infinity)

(1/3) = 0.333...

Three divided by one equals three

(3/1) = 3

Also, since fractions are multiplied numerator*numerator and denominator*denominator:

**(1/3)*(3/1)**= (3/3) =

__1__

Keep in mind that 3*3 = 9, so it follows that:

**(1/3)*3**= (0.333...)*3 =

__(0.999...)__

We've used the same equation to achieve two distinct answers (3 and 3/1 are equal, remember!). Simple Junior High math allows use to substitute and eliminate common factors, so we are left with:

**0.999... = 1**

If you have a way of resolving this paradox, please post!

Cheers,

Iron Duke